(x)=3x^2+24x+48

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Solution for (x)=3x^2+24x+48 equation: 



(x)=3x^2+24x+48

We move all terms to the left:

(x)-(3x^2+24x+48)=0

We get rid of parentheses

-3x^2+x-24x-48=0

We add all the numbers together, and all the variables

-3x^2-23x-48=0

a = -3; b = -23; c = -48;
Δ = b2-4ac
Δ = -232-4·(-3)·(-48)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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